From: Bill Findlay <yaldnif.w@blueyonder.co.uk>
Subject: Re: character literals
Date: 11 Feb 2014 23:45:53 GMT
Date: 2014-02-11T23:45:53+00:00 [thread overview]
Message-ID: <887860151413854987.949178yaldnif.w-blueyonder.co.uk@news.individual.net> (raw)
In-Reply-To: lde9d6$dmt$1@dont-email.me
"J-P. Rosen" <rosen@adalog.fr> wrote:
> Le 11/02/2014 23:27, agent@drrob1.com a écrit :
>> I have been having a difficulty in my code with character literals.
>> For example
>>
>> IF ch in '0' .. '9' THEN
>>
>> This gives an error because the compiler is complaining that it does
>> not know if I mean a character, wide_character, or wide_wide_character
>> for my literals. How do I indicate which I want?
>>
> if Ch in Character range '0' .. '9' then
>
> Ada recognizes types by name. There are a few cases (like this one)
> where the designers tried to save some typing by allowing the type to be
> inferred from the values; it is almost always a bad idea, and it is
> always possible to state the type explicitely.
Why is the literal type not inferred from the type of Ch in this case?
--
Bill Findlay
next prev parent reply other threads:[~2014-02-11 23:45 UTC|newest]
Thread overview: 17+ messages / expand[flat|nested] mbox.gz Atom feed top
2014-02-11 22:27 character literals agent
2014-02-11 22:49 ` J-P. Rosen
2014-02-11 23:45 ` Bill Findlay [this message]
2014-02-11 23:49 ` Ludovic Brenta
2014-02-11 23:58 ` adambeneschan
2014-02-11 23:56 ` adambeneschan
2014-02-12 0:18 ` adambeneschan
2014-02-12 1:34 ` agent
2014-02-12 2:03 ` adambeneschan
2014-02-12 12:50 ` agent
2014-02-12 1:30 ` Jeffrey Carter
2014-02-12 1:50 ` adambeneschan
2014-02-12 15:53 ` Robert A Duff
2014-02-12 17:55 ` J-P. Rosen
2014-02-14 12:39 ` agent
2014-02-14 18:36 ` AdaControl was: " Simon Clubley
2014-02-15 6:26 ` J-P. Rosen
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