Re: character literals

[Ludovic Brenta <ludovic@ludovic-brenta.org>]

Bill Findlay writes on comp.lang.ada:
> "J-P. Rosen" wrote:
>> Le 11/02/2014 23:27, agent@drrob1.com a écrit :
>>> I have been having a difficulty in my code with character literals.
>>> For example
>>> 
>>>  IF ch in '0' .. '9' THEN
>>> 
>>> This gives an error because the compiler is complaining that it does
>>> not know if I mean a character, wide_character, or wide_wide_character
>>> for my literals.  How do I indicate which I want?
>>> 
>> if Ch in Character range '0' .. '9' then
>> 
>> Ada recognizes types by name. There are a few cases (like this one)
>> where the designers tried to save some typing by allowing the type to be
>> inferred from the values; it is almost always a bad idea, and it is
>> always possible to state the type explicitely.
>
> Why is the literal type not inferred from the type of Ch in this case?

Because it's the other way around :) the type of Ch is inferred from the
type of the range.

-- 
Ludovic Brenta.