Re: Exit Loop_Statement

["David Freshwater" <dafresh@odyssey.apana.org.au>]

Hi,
   Thanks for the help....I had picked up the (1..3) error.
I actually have written 2 programs for this assignment. One works well, the
other is a different approach to what we have been taught. Let me point out
that I am an external student studying this, which makes it hard as I don't
have any one to bounce ideas off or get any helpful input. So any help
whether pointers or snippets of code are really appreciated.
I do understand the need to do this by myself but it just gets frustrating.

David
Robert Dewar <robert_dewar@my-deja.com> wrote in message
news:8f91ps$vb3$1@nnrp1.deja.com...
> In article <3917C83E.D088C4DF@bton.ac.uk>,
>   John English <je@bton.ac.uk> wrote:
> > That should be Clients(1..4), right?
>
> Well yes, of course, and of course we all saw that. But don't
> you think it is instructive for people to find a bug like that
> for themselves. I preferred the previous post which gave a
> useful pointed hint (think about whether this will ever be
> true), to this one that provides the correction directly.
>
> A hard part of computer programming is figuring out why what
> you have written does not work, and learning to be careful
> and avoid writing such things in the first place. Practice
> is really essential in this task. The purpose of assignments
> is to provide this practice, and you have to be careful that
> in an attempt to be helpful you do not bypass this very
> important function.
>
> > You should convert to e.g. lower case if you want case
> > insensitivity:
> >   if Ada.Characters.Handling.To_Lower(Clients(1..4)) = "stop"
> > then ...
>
> Again, I would point to the reference for this routine, rather
> than give the exact code, which the student can then just cut
> and paste without any understanding.
>
>
>
>
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