Re: how to round integers (Figured it out!)

From: "David C. Hoos" <david.c.hoos.sr@ada95.com>
Subject: Re: how to round integers (Figured it out!)
Date: Mon, 16 Jun 2003 07:34:07 -0500
Date: 2003-06-16T07:34:07-05:00	[thread overview]
Message-ID: <verea54p433q7f@corp.supernews.com> (raw)
In-Reply-To: verddee9cbo317@corp.supernews.com

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It's simpler to just add one less than the divisor to the dividend before
dividing.

"Cephus�" <beau@hiwaay.net> wrote in message
news:verddee9cbo317@corp.supernews.com...
>
>
> Cephus� wrote:
> > I am trying to remember the "golden rule" for integer division
> > rounding.
> >
> > I am trying to average something (both integers) and I can't remember
> > how to round without using floating point.
> >
> > Like say I am trying to divide 26/3  --- I would get 8 remainder 2
> >
> > but that should round up to 9. How can I do this? I know it has
> > something to do with the dividend....but I can't for the life of me
> > remember. thanks!
> >
> > Beau
>
> I figured it out. Thanks for the help (although I was asking how to do
> something, not the code to do it, usually you would never get that in a
> newsgroup).
>
> All you do is REM the divisor and dividend. Then double it. If that number
> is greater than the divisor, then add one. Otherwise don't...
>
> Beau
>
>
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