Re: Arrays in Ada 2012

["Dmitry A. Kazakov" <mailbox@dmitry-kazakov.de>]

On 06/06/2017 13:47, Anatoly Chernyshev wrote:

> Consider the following nice Ada 2012 construct:
> 
> --
> procedure test is
>     type a1 is array(1..35,1..35,1..35,1..35,1..35,1..35) of long_long_integer;
>     ab:a1;
>     cnt:long_long_integer:=0;
> begin
>    for e of ab loop
>        cnt:=cnt+1;
>        e:=cnt;
>     end loop;
> end test;
> --
> 
> Is there a way (e.g. some attribute) to find the indices of the
> array  for a current e within the cycle above?

The greater dimension index changes first, so:

I6 := Count mod 35 + 1;
I5 := (Count / 35) mod 35 + 1;
I4 := (Count / 35**2) mod 35 + 1;
I3 := (Count / 35**3) mod 35 + 1;
I2 := (Count / 35**4) mod 35 + 1;
I1 := Count / 35**5 + 1;

-- 
Regards,
Dmitry A. Kazakov
http://www.dmitry-kazakov.de