RE: Integers and Mathematical Correctness

["Beard, Frank" <beardf@spawar.navy.mil>]

-----Original Message-----
From: chris.danx [mailto:chris.danx@ntlworld.com]

> why does
>
> xxx : c_integer := c_integer(-3)/c_integer(2);  work then?
                                  ^
Because --------------------------^ this operator
is inherited from integer for the new type.  This
division operator is for the new derived type
c_integer.  Remember "new" causes it to be treated as
a unique type (i.e. they can't be intermixed without
conversion).


>Is it not the same?
No, it's for the derived type.

Now if you did the following, it would be the same
(same being, it would use Standard integer).

xxx : c_integer := c_integer(-3/2);

or maybe

xxx : c_integer := c_integer(integer(-3)/integer(2));

The first may be universal integer, whereas, the second
is integer.

Frank