"sizeof" a record

"sizeof" a record

[mop]

how do i obtain the "sizeof" a record?

I've got 8 bytes of data for one record
and 517 bytes for another

Re: "sizeof" a record

[Marin David Condic]

You should be able to do Record_Type'Size or Record_Object'Size which
returns the size in bits. You probably want to divide by System.Storage_Unit
to get the size in bytes. (If your machine has System.Storage_Unit = 8)

Read through Annex K of the ARM - you'll find lots of useful attributes
there that are especially handy for low level programming or dealing with
machine dependencies.

MDC
--
Marin David Condic
Senior Software Engineer
Pace Micro Technology Americas    www.pacemicro.com
Enabling the digital revolution
e-Mail:    marin.condic@pacemicro.com
Web:      http://www.mcondic.com/


"mop" <mop65715@pegasus.cc.ucf.edu> wrote in message
news:9nj40t$qbr$1@zeus.orl.lmco.com...
>
> how do i obtain the "sizeof" a record?
>
> I've got 8 bytes of data for one record
> and 517 bytes for another
>
>
>
>

Re: "sizeof" a record

[David C. Hoos]

Please refer to theAda Language Reference Manual, Annex K
paragraphs 223-229, inclusive.

----- Original Message ----- 
From: "mop" <mop65715@pegasus.cc.ucf.edu>
Newsgroups: comp.lang.ada
To: <comp.lang.ada@ada.eu.org>
Sent: Monday, September 10, 2001 2:24 PM
Subject: "sizeof" a record


> 
> how do i obtain the "sizeof" a record?
> 
> I've got 8 bytes of data for one record
> and 517 bytes for another
> 
> 
> 
> 
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