From: "Randy Brukardt" <randy@rrsoftware.com>
Subject: Re: How difficult is ada to learn?
Date: Thu, 30 Jun 2005 13:59:20 -0500
Date: 2005-06-30T13:59:20-05:00 [thread overview]
Message-ID: <mMKdnfE-XpTQ3VnfRVn-qg@megapath.net> (raw)
In-Reply-To: 42c40313$0$32193$39cecf19@news.twtelecom.net
"Matthew Heaney" <mheaney@on2.com> wrote in message
news:42c40313$0$32193$39cecf19@news.twtelecom.net...
Matt Heaney wrote:
> If not having "built-in" syntax is a hardship, then you can always
> define array-based set operations yourself. For example, suppose we
> have a set whose element type is Integer, then we can do this:
The following example seems pretty confused.
> type Integer_Array is array (Positive range <>) of Integer;
>
> function "+" (IA : Integer) return Integer_Sets.Set is
What's the definition of "Integer_Sets.Set"? Shouldn't IA have type
Integer_Array, rather than Integer?
> S : Set;
> begin
> for Indx in IA'Range loop
> S.Include (IA (Indx));
> end loop;
>
> return S;
> end;
>
> Now you can say:
>
> declare
> S1 : Set := +(1, 2, 3);
> S2 : Set := +(2, 3, 4);
> S3 : Set := S1 or S2;
> S4 : Set := S3 and +(1, 3);
> S5 : Set := +(42, 43) or +(44, 45);
Presuming that Integer_Sets.Set has "or" and "and" operations.
Randy.
next prev parent reply other threads:[~2005-06-30 18:59 UTC|newest]
Thread overview: 20+ messages / expand[flat|nested] mbox.gz Atom feed top
2005-06-30 0:44 How difficult is ada to learn? Sm704
2005-06-30 5:11 ` Ludovic Brenta
2005-06-30 6:15 ` Preben Randhol
2005-06-30 14:19 ` Gene
2005-06-30 14:34 ` Matthew Heaney
2005-06-30 15:00 ` Duncan Sands
2005-06-30 18:38 ` Gene
2005-06-30 19:32 ` Matthew Heaney
2005-06-30 18:59 ` Randy Brukardt [this message]
2005-06-30 19:36 ` Matthew Heaney
2005-06-30 15:01 ` Matthew Heaney
2005-06-30 22:35 ` Robert A Duff
2005-07-15 2:27 ` Waldek Hebisch
2005-07-15 5:14 ` Ludovic Brenta
2005-07-01 5:37 ` Jeffrey Carter
2005-06-30 16:43 ` Martin Krischik
2005-06-30 19:36 ` svaa
2005-06-30 22:53 ` chris
2005-06-30 22:54 ` chris
2005-07-01 5:39 ` Jeffrey Carter
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