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* Abstract operator does not hide predefined operator
@ 2010-11-12 15:04 Stefan.Lucks
  2010-11-12 16:56 ` Adam Beneschan
  0 siblings, 1 reply; 3+ messages in thread
From: Stefan.Lucks @ 2010-11-12 15:04 UTC (permalink / raw)


Hi all,

I've implemented a small generic package for modular arithmetic. Note that 
Ada's "mod N" types define addition subtraction and multiplication right, 
but use the integer division for "/" instead of the proper modular 
division, where A/B is A * Inverse(B). I also tried to get rid of the 
unary "not" operator, who's purpose I don't understand for general 
modular arithmetic. (I understand that it is useful if the modulus is a 
power of two, just like the binary xor operator.)

This is the spec of my generic package:

generic
   type Mod_T is mod <>;
package Mod_Arith is
   type Modular is new Mod_T;
   function "/"(Left, Right: Modular) return Modular;
   function Inverse(Value: Modular) return Modular;
   function "not"(Value: Modular) return Modular is abstract;
end Mod_Arith;

For testing that package, I first instantiated it:

   type M3343 is mod 3343;
   package M is new Mod_Arith(Mod_T => M3343);
   use type M.Modular;
   S,T,U: M.Modular;

(Sidenote: 3343 is a prime, so addition and multiplication over M.Modular 
are field operations, mathematically.)

Now, my freshly defined division works as expected. The multiplication 
(and addition and subtraction) are inherited from the type M3343:

   S := 3;
   T := S/(2*S); -- T becomes the multiplicative Inverse of 2 mod 3343; 
                 -- the same expression's result in M3343 would be zero.
   Ada.Text_IO.Put_Line(M.Modular'Image(T) &
                          M.Modular'Image(M.Inverse(2)));
   -- The output is "1672 1672", as expected. 

But, unfortunately, the compiler (gnat) also accepts the following:

   U := not S; -- this should not be possible, because the "not" operator
               -- has been defined abstract ... but instead, the 
               -- predefined "not" from M3343 seems to be used
   Ada.Text_IO.Put_Line(M.Modular'Image(U));
   -- The output is "3339", which actually is not(M3343(S)) = 3342-S. 

What can I do to get rid of the predefined "not"? If I change the "not" 
from an abstract function to a function always raising an exception, the 
statement 

   U := not S;

raises the desired exception. But I would prefer to be told at compile 
time that I must not use "not", rather than at run time. Also, I would 
prefer not to define the type Mod_Arith.Modular as a private type.

Any ideas?

Stefan



-- 
------ Stefan Lucks   --  Bauhaus-University Weimar  --   Germany  ------
               Stefan dot Lucks at uni minus weimar dot de
------  I  love  the  taste  of  Cryptanalysis  in  the  morning!  ------




^ permalink raw reply	[flat|nested] 3+ messages in thread

* Re: Abstract operator does not hide predefined operator
  2010-11-12 15:04 Abstract operator does not hide predefined operator Stefan.Lucks
@ 2010-11-12 16:56 ` Adam Beneschan
  2010-11-12 17:39   ` Alex Mentis
  0 siblings, 1 reply; 3+ messages in thread
From: Adam Beneschan @ 2010-11-12 16:56 UTC (permalink / raw)


On Nov 12, 7:04 am, Stefan.Lu...@uni-weimar.de wrote:
> Hi all,
>
> I've implemented a small generic package for modular arithmetic. Note that
> Ada's "mod N" types define addition subtraction and multiplication right,
> but use the integer division for "/" instead of the proper modular
> division, where A/B is A * Inverse(B). I also tried to get rid of the
> unary "not" operator, who's purpose I don't understand for general
> modular arithmetic. (I understand that it is useful if the modulus is a
> power of two, just like the binary xor operator.)
>
> This is the spec of my generic package:
>
> generic
>    type Mod_T is mod <>;
> package Mod_Arith is
>    type Modular is new Mod_T;
>    function "/"(Left, Right: Modular) return Modular;
>    function Inverse(Value: Modular) return Modular;
>    function "not"(Value: Modular) return Modular is abstract;
> end Mod_Arith;
>
> For testing that package, I first instantiated it:
>
>    type M3343 is mod 3343;
>    package M is new Mod_Arith(Mod_T => M3343);
>    use type M.Modular;
>    S,T,U: M.Modular;
>
> (Sidenote: 3343 is a prime, so addition and multiplication over M.Modular
> are field operations, mathematically.)
>
> Now, my freshly defined division works as expected. The multiplication
> (and addition and subtraction) are inherited from the type M3343:
>
>    S := 3;
>    T := S/(2*S); -- T becomes the multiplicative Inverse of 2 mod 3343;
>                  -- the same expression's result in M3343 would be zero.
>    Ada.Text_IO.Put_Line(M.Modular'Image(T) &
>                           M.Modular'Image(M.Inverse(2)));
>    -- The output is "1672 1672", as expected.
>
> But, unfortunately, the compiler (gnat) also accepts the following:
>
>    U := not S; -- this should not be possible, because the "not" operator
>                -- has been defined abstract ... but instead, the
>                -- predefined "not" from M3343 seems to be used
>    Ada.Text_IO.Put_Line(M.Modular'Image(U));
>    -- The output is "3339", which actually is not(M3343(S)) = 3342-S.
>
> What can I do to get rid of the predefined "not"? If I change the "not"
> from an abstract function to a function always raising an exception, the
> statement
>
>    U := not S;
>
> raises the desired exception. But I would prefer to be told at compile
> time that I must not use "not", rather than at run time. Also, I would
> prefer not to define the type Mod_Arith.Modular as a private type.
>
> Any ideas?

This appears to be a GNAT bug; the inherited "not" subprogram of
Modular, which is inherited from the predefined function of M3343,
exists but should be hidden from all visibility, and therefore cannot
be a possible meaning of "not" in the expression "not S".  So what
you're doing should work, I think.  (P.S. I've confirmed that the
version of GNAT I'm using also accepts the program if I write out M
instead of making it a generic instantiation, and if I use "use"
instead of "use type".  So neither of those appears to be an issue.)

                              -- Adam



^ permalink raw reply	[flat|nested] 3+ messages in thread

* Re: Abstract operator does not hide predefined operator
  2010-11-12 16:56 ` Adam Beneschan
@ 2010-11-12 17:39   ` Alex Mentis
  0 siblings, 0 replies; 3+ messages in thread
From: Alex Mentis @ 2010-11-12 17:39 UTC (permalink / raw)


Adam Beneschan wrote:

> On Nov 12, 7:04�am, Stefan.Lu...@uni-weimar.de wrote:
> > Hi all,
> > 
> > I've implemented a small generic package for modular arithmetic.
> > Note that Ada's "mod N" types define addition subtraction and
> > multiplication right, but use the integer division for "/" instead
> > of the proper modular division, where A/B is A * Inverse(B). I also
> > tried to get rid of the unary "not" operator, who's purpose I don't
> > understand for general modular arithmetic. (I understand that it is
> > useful if the modulus is a power of two, just like the binary xor
> > operator.)
> > 
> > This is the spec of my generic package:
> > 
> > generic
> > � �type Mod_T is mod <>;
> > package Mod_Arith is
> > � �type Modular is new Mod_T;
> > � �function "/"(Left, Right: Modular) return Modular;
> > � �function Inverse(Value: Modular) return Modular;
> > � �function "not"(Value: Modular) return Modular is abstract;
> > end Mod_Arith;
> > 
> > For testing that package, I first instantiated it:
> > 
> > � �type M3343 is mod 3343;
> > � �package M is new Mod_Arith(Mod_T => M3343);
> > � �use type M.Modular;
> > � �S,T,U: M.Modular;
> > 
> > (Sidenote: 3343 is a prime, so addition and multiplication over
> > M.Modular are field operations, mathematically.)
> > 
> > Now, my freshly defined division works as expected. The
> > multiplication (and addition and subtraction) are inherited from
> > the type M3343:
> > 
> > � �S := 3;
> > � �T := S/(2*S); -- T becomes the multiplicative Inverse of 2 mod
> > 3343; � � � � � � � � �-- the same expression's result in M3343
> > would be zero.  � �Ada.Text_IO.Put_Line(M.Modular'Image(T) &
> > � � � � � � � � � � � � � M.Modular'Image(M.Inverse(2)));
> > � �-- The output is "1672 1672", as expected.
> > 
> > But, unfortunately, the compiler (gnat) also accepts the following:
> > 
> > � �U := not S; -- this should not be possible, because the "not"
> > operator � � � � � � � �-- has been defined abstract ... but
> > instead, the � � � � � � � �-- predefined "not" from M3343 seems to
> > be used � �Ada.Text_IO.Put_Line(M.Modular'Image(U));
> > � �-- The output is "3339", which actually is not(M3343(S)) =
> > 3342-S.
> > 
> > What can I do to get rid of the predefined "not"? If I change the
> > "not" from an abstract function to a function always raising an
> > exception, the statement
> > 
> > � �U := not S;
> > 
> > raises the desired exception. But I would prefer to be told at
> > compile time that I must not use "not", rather than at run time.
> > Also, I would prefer not to define the type Mod_Arith.Modular as a
> > private type.
> > 
> > Any ideas?
> 
> This appears to be a GNAT bug; the inherited "not" subprogram of
> Modular, which is inherited from the predefined function of M3343,
> exists but should be hidden from all visibility, and therefore cannot
> be a possible meaning of "not" in the expression "not S".  So what
> you're doing should work, I think.  (P.S. I've confirmed that the
> version of GNAT I'm using also accepts the program if I write out M
> instead of making it a generic instantiation, and if I use "use"
> instead of "use type".  So neither of those appears to be an issue.)
> 
>                               -- Adam

Agree that it smells buggy.  It seems that the problem only affects
making unary operators abstract ("-" and "not"). Testing with "+", "-",
"/", "*", "and", "or", and "xor" operators as abstract refused to
compile as expected for me.



^ permalink raw reply	[flat|nested] 3+ messages in thread

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