Using records properly.

Using records properly.

[McDoobie]

So I have this record in my spec file that goes like this ...

type people_entries is record
        person_name : String( 1..80 );
        person_addr  : String( 1..80 );
        person_num  : String(  1..80 );
        person_mail  :  String( 1..80 );
end record;


Now, I know how to store the information in the record...


NewRec : people_entries;

NewRec := person_name(aName); 

etc....

Now, would I use a "NewRec" for each field, or would I go something like...

NewRec := (aName, aAddr, aNum, aMail);

I'm a little fuzzy on this. 
And how would I tag each record to make it unique, cause all the computer 
is gonna see is "NewRec" and overwrite the last record for each new one 
that is entered.

Thanks.

McDoobie


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Re: Using records properly.

[Ted Dennison]

In article <86Rr6.57913$W05.11839272@news1.rdc1.mi.home.com>, McDoobie says...
>type people_entries is record
>        person_name : String( 1..80 );
>        person_addr  : String( 1..80 );
>        person_num  : String(  1..80 );
>        person_mail  :  String( 1..80 );
>end record;
>
>
>Now, I know how to store the information in the record...
>
>
>NewRec : people_entries;
>
>NewRec := person_name(aName); 

The syntax would be something a bit more like 
NewRec.Person_Name := aName;
(assuming aName is an 80 character string)

>NewRec := (aName, aAddr, aNum, aMail);
That'll work too (again, assuming all of your a* stuff are 80 character
strings).

>I'm a little fuzzy on this. 
You should really try to get hold of a decent Ada book. This is pretty basic
stuff, and I doubt you want to try to learn *all* the basics one question at a
time in newsgroups. (right?)


---
T.E.D.    homepage   - http://www.telepath.com/dennison/Ted/TED.html
          home email - mailto:dennison@telepath.com

Re: Using records properly.

[McDoobie]

Ted Dennison wrote:

> In article <86Rr6.57913$W05.11839272@news1.rdc1.mi.home.com>, McDoobie
> says...
> >type people_entries is record
> >        person_name : String( 1..80 );
> >        person_addr  : String( 1..80 );
> >        person_num  : String(  1..80 );
> >        person_mail  :  String( 1..80 );
> >end record;
> >
> >
> >Now, I know how to store the information in the record...
> >
> >
> >NewRec : people_entries;
> >
> >NewRec := person_name(aName);
> 
> The syntax would be something a bit more like
> NewRec.Person_Name := aName;
> (assuming aName is an 80 character string)
> 
> >NewRec := (aName, aAddr, aNum, aMail);
> That'll work too (again, assuming all of your a* stuff are 80 character
> strings).
> 
> >I'm a little fuzzy on this.
> You should really try to get hold of a decent Ada book. This is pretty
> basic stuff, and I doubt you want to try to learn *all* the basics one
> question at a time in newsgroups. (right?)
> 
> 
> ---
> T.E.D.    homepage   - http://www.telepath.com/dennison/Ted/TED.html
>           home email - mailto:dennison@telepath.com


Your right. Heh.

I've pretty much been using the online tutorials and documentation to pick 
up this stuff.

Looks like I'm off to Barnes and Noble. There have been some good book 
recommendations here. I'll look them up.

McDoobie


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This is my sig.