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From: "Hibou57 (Yannick Duchêne)" <yannick_duchene@yahoo.fr>
Subject: Re: How to convert a string containing two hex digits to a character?
Date: Sat, 9 Jan 2010 06:50:17 -0800 (PST)
Date: 2010-01-09T06:50:17-08:00	[thread overview]
Message-ID: <e675a8cf-fc27-4987-ac9c-23e50e828bd9@m3g2000yqf.googlegroups.com> (raw)
In-Reply-To: 2m4g35mnk59z$.xhxh0f7riqad.dlg@40tude.net

On 9 jan, 12:33, "Dmitry A. Kazakov" <mail...@dmitry-kazakov.de>
wrote:
> No. Addition is an operation (in an Abelian group) that may exist
> independently on the order relation. As an example consider the complex
> numbers, which is a field. As such it has addition and subtraction.
> Nevertheless it lacks order, and thus there is no Complex'Pred or
> Complex'Succ. And conversely, there can be an order, but no addition.
> Example: String.
>
> The guide line should be the semantics. If it is an iteration intended,
> then T'Succ is a clear favorite, just because x + 1 has nothing to do with
> enumeration. Unfortunately T'Succ is much too verbose, because it
> unnecessarily refers to the type.
Nice to read you

Not “ No ”, while True as well. Right that it is not the only way to
define it.

You may define the attraction as the opposite of the repulsion, or you
may define the repulsion as the opposite of the attraction. In some
area, you may define Pred and Succ based on “ + ” and “ - ”, or in an
as good way, define + and - based on Pred and Succ.

There are no Pred and Succ on reals, complexes and the likes, but
their “ + ” and “ - ” are not either the same too (homonym, but
different things), and that's because their “ + ” and “ - ” are not
the same that they do not have a Pred and Succ.

This topic is a lot attractive



  reply	other threads:[~2010-01-09 14:50 UTC|newest]

Thread overview: 22+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2010-01-06  0:39 How to convert a string containing two hex digits to a character? Leslie
2010-01-06  0:43 ` Leslie
2010-01-06  1:22   ` Hibou57 (Yannick Duchêne)
2010-01-06  1:31     ` Hibou57 (Yannick Duchêne)
2010-01-06  2:05       ` Leslie
2010-01-06  2:39     ` Leslie
2010-01-06  2:42       ` Leslie
2010-01-06 21:54     ` Maciej Sobczak
2010-01-06 22:19       ` Hibou57 (Yannick Duchêne)
2010-01-09 10:50         ` Hibou57 (Yannick Duchêne)
2010-01-09 11:13           ` Hibou57 (Yannick Duchêne)
2010-01-09 11:33             ` Dmitry A. Kazakov
2010-01-09 14:50               ` Hibou57 (Yannick Duchêne) [this message]
2010-01-09 16:04                 ` Dmitry A. Kazakov
2010-01-11 15:53                   ` Adam Beneschan
2010-01-11 18:13                     ` Dmitry A. Kazakov
2010-01-15 19:59                     ` Hibou57 (Yannick Duchêne)
2010-01-15 22:06                       ` John B. Matthews
2010-01-06  5:17 ` tmoran
2010-01-06 22:19   ` Leslie
2010-01-06 22:22   ` Hibou57 (Yannick Duchêne)
2010-01-07 14:26 ` John B. Matthews
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