Re: Task discriminants

["Martin Dowie" <martin.dowie@btopenworld.com>]

function Next_Id return Integer;

task type A_Task (Id : Integer := Next_Id);

Id : Integer := 0;

function Next_Id return Integer is
begin
   Id := Id + 1;
   return Id;
end Next_Id;

The_Tasks : array (1 .. 3) of A_Task;

You could consider putting Id and Next_Id in their own package.

Cheers

-- Martin


"David C. Hoos" <david.c.hoos.sr@ada95.com> wrote in message
news:mailman.1.1085073466.401.comp.lang.ada@ada-france.org...
> How about:
>
> The_Tasks: array (1 .. 3) of A_Task =
>  (A_Task (1),
>   A_Task (2),
>   A_Task (3)
>  );
> ----- Original Message ----- 
> From: "Dave Levy" <dlevy@mail.usyd.edu.au>
> Newsgroups: comp.lang.ada
> To: <comp.lang.ada@ada-france.org>
> Sent: Thursday, May 20, 2004 9:47 AM
> Subject: Task discriminants
>
>
> > Hi
> >
> > Suppose one has a task type with a discriminant:
> >
> >     task type A_Task( Id : integer);
> >
> > and one wishes to declare a set of tasks with initialised discriminants:
> >     t1 : A_Task(1);
> >     t2 : A_Task(2);
> >     t3 : A_Task(3);
> >
> > How could one declare them as an array of tasks with each one getting an
> > initialised discriminant? Perhaps something like:
> >
> >     The_Tasks: array (1..3) of A_Task( Id => 1,2,3 );
> >
> > Except I tried this with Gnat and it won't compile.
> >
> > Thanks
> >
> > Dave
> >
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> >