From: "Martin Dowie" <martin.dowie@btopenworld.com>
Subject: Re: my program
Date: Mon, 29 Dec 2003 23:02:16 +0000 (UTC)
Date: 2003-12-29T23:02:16+00:00 [thread overview]
Message-ID: <bsqbpo$b20$1@sparta.btinternet.com> (raw)
In-Reply-To: bspfvv$mpo$1@atlantis.news.tpi.pl
"Kasia Krysiak" <kasiool@o2.pl> wrote in message
news:bspfvv$mpo$1@atlantis.news.tpi.pl...
> I'm start to lern ada , and i have some problems...
> this is my new program, and i have a question how to inicialize
> Task1:Male(Id=>1); Task2:Male(Id=>2); task3:male(id=>3); (last 3 lines of
> code in loop? becouse i should to have the number od male dymaic. I
tryided
> to do this in arry but i couldnt inlicjalize this id's sorry 4 my english
> it isnt good I KNOW!!! - but I'm trying :)
> task type Male(Id: integer);
[snip]
> Task1:Male(Id=>1);
>
> Task2:Male(Id=>2);
>
> task3:male(id=>3);
You can do this at elaboration:
package body Foo is
Task_Id : Natural := 0;
function Get_Id return Positive is
begin
Task_Id := Task_Id + 1;
return Task_Id;
end Get_Id;
task type Bar (Id : Natural := Get_Id);
task body Bar is ... end Bar;
Tasks : array (1 .. 3) of Bar;
end Foo;
The Lawyers can correct me if I'm wrong but elaboration is
performed sequentially and therefore the Id's are guaranteed
to be unique.
prev parent reply other threads:[~2003-12-29 23:02 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2003-12-29 15:07 my program Kasia Krysiak
2003-12-29 18:16 ` Martin Krischik
2003-12-29 23:02 ` Martin Dowie [this message]
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