Re: question on using `with` without `use` and visibility of operators such as '*'

[Niklas Holsti <niklas.holsti@tidorum.invalid>]

On 12-07-30 09:04 , Nasser M. Abbasi wrote:
> <warning, newbie in Ada>
> 
> I prefer to use the long name of a package when I call some of its
> functions. So I like to write
> 
> ------------------------
> with package_foo;
>    package_foo.function_name();
> -----------------------
> 
> rather than
> 
> -----------------------
> with package_foo; use package_foo;
>   function_name();
> ----------------------
> 
> So that when reading the code, I know where things are.
> 
> This worked well so far, but when the package happened to export
> functions/operators  such as '*' or "+" for the types, then it will
> not work any more. i.e. I really want to just write
> 
>            x * y
> 
> where x,y are variables with types defined in the package, and not write
> 
>            x package_foo("*") y
> 
> (or whatever the correct syntax would be)
> 
> This is annoying. It means I have now to `use package_foo`
> to be able to write  x*y, since "*" is defined in the package.
> 
> Is there a way around this, so I can avoid using `use` but still
> be able to just write   x * y  (may be use something like
> `use package_foo("*") at the top if this possible)

Use "use type package_foo.T", where T is the type of x and y. Then you
can apply the "primitive operators" of the type with qualifying with the
package name.

See the "use_type_clause" in
http://www.ada-auth.org/standards/12rm/html/RM-8-4.html.

Note the additional names made visible when the "all" keyword is placed
between "use" and "type".

-- 
Niklas Holsti
Tidorum Ltd
niklas holsti tidorum fi
      .      @       .