Re: Question on types conversions - operations

[anon@anon.org (anon)]

How about :

  S := Speed ( L ) / Speed ( T ) ;

I prefer simplier, convert to resulting type then preform the algorithm.



In <4a33cb0b$0$2848$ba620e4c@news.skynet.be>, Olivier Scalbert <olivier.scalbert@algosyn.com> writes:
>Hello,
>
>I have the following three types:
>     type Length is new Float;
>     type Time   is new Float;
>     type Speed  is new Float;
>
>Suppose I need to compute a speed given a length and a time.
>
>     L: Length := 100.0;
>     T: Time   :=  10.0;
>     S: Speed;
>
>How to do that ?
>
>With S := Speed(Float(L) / Float(T)) ? Mmmm ... not nice.
>
>With S := Speed(L / Length(T)), I am also not satisfy as I convert a 
>time in Length ...
>
>I am sure you have better ideas !
>
>Good weekend,
>
>Olivier