Re: How to put 200 into an integer sub-type of 16 bits (code included)

["SteveD@teranews.com" <nospam_steved94@comcast.net>]

"ChristopherL" <clusardi2k@aol.com> wrote in message 
news:c265ffb7-6159-4d85-b259-78b830e115f9@v18g2000pro.googlegroups.com...
[snip]
>
>So, what is the proper way to store a number (never being greater than
>200.5) in a 8 bit
>short number as outlined above?
>
>
>Chris L.

I've been watching this thread trying to figure out what it is you're trying 
to do and I still don't get it.

It appears that you are trying to store values in the range of 0 to 200.5 in 
8 bits.  Are you trying to store a bunch of data values in a small amount of 
memory?  Are you trying to minimize bandwidth for communication?

What it comes down to is this:
  With an 8 bit number you have the ability to distinguish 256 values.  If 
you want to get the best resolution possible for values in the range of 0.0 
to 200.5 that you can store in 8 bits, create a linear mapping such that 0.0 
maps to 0 and 200.5 maps to 255.
  8 bit value = 255.0/200.5 * floatValue

  To retrieve the value, do the reverse mapping:
   floatValue = 200.5/255.0 * 8 bit value

  You probably want to use a lookup table if you're processing a bunch of 
data.

But then again, I'm still unclear on what you're trying to do.

Regards,
Steve