Re: type Foo_ptr in new void*;

[taw@pb220.legnica.sdi.tpnet.pl (Tomasz Wegrzanowski)]

In article <3B63F48A.2E2642C6@earthlink.net>, Marc A. Criley wrote:
>> I can't do this.
>> Foo is supposed to be used only as a pointer.
>> I don't know if newer version of library will use the same Foo.
> 
> In tmoran's post, wherever you saw "in out Foo", change it to "in
> Foo_Pointer".
> 
> In order to declare a pointer to a type, you have to have that type's
> definition.  Even C requires that for "foo*" there be some declaration
> of "foo".

Not true.
You can use `struct Foo *' without declaring `struct Foo'.
You can `typedef struct Foo Foo_t;' or `typedef struct Foo *Foo_p;'
and use Foo_t and Foo_p w/o declaring `struct Foo'.