Re: Three of a crime Card game

[gattamaneni abhiram <abhiram.gattamaneni@gmail.com>]

On Tuesday, 26 March 2013 23:10:31 UTC-4, Dennis Lee Bieber  wrote:
> On Tue, 26 Mar 2013 16:18:10 -0700 (PDT), gattamaneni abhiram
> 
> <abhiram.gattamaneni@gmail.com> declaimed the following in
> 
> comp.lang.ada:
> 
> 
> 
> > Three-of-a-crime is a simple logic game for up to 3 players. There are 7 different 
> 
> > criminals. The computer randomly chooses three of these (the "perpetrators"), but 
> 
> > doesn't tell the players which are chosen. The computer then puts down three random 
> 
> > criminals. 0, 1, or 2 of these may be the actual perpetrators. The computer also tells 
> 
> > the player how many (but not which) of the three criminals are perpetrators. The 
> 
> > players may either guess which three criminals are the actual perpetrators or they may 
> 
> > pass. If a player guesses wrong, she is out of the game and the other players continue. 
> 
> > If no player chooses to guess, the computer puts down another three randomly chosen 
> 
> > criminals (0, 1, or 2 of which may be actual perpetrators) and tells the players how 
> 
> > many (but not which) of these are actual perpetrators. Players can again use logic to 
> 
> > deduce the three actual criminals and may guess. Play continues until some player 
> 
> > guesses correctly or until all players have guessed incorrectly. 
> 
> > 
> 
> > I am not able to deduce the logic. Can anyone please help me with the logic? 
> 
> 
> 
> 	Given your description, this is NOT a "simple logic game"... There
> 
> is, in your description, NO LOGIC to apply. That is, there are NO clues
> 
> provided to the players.
> 
> 
> 
> 	Consider:
> 
> 
> 
> 7 candidate suspects
> 
> 3 of the 7 are guilty (perpetrators)
> 
> 3 of the 7 are listed to the players (these three may or may not be in
> 
> the list of guilty)
> 
> "computer also tells the player how many": OKAY, ONE CLUE... but if the
> 
> computer says "0", then there is nothing for a player to do. Similarly,
> 
> if the computer says "3", then all of the listed names are guilty --
> 
> again, nothing for a player to do.
> 
> 
> 
> Therefore, the only "play" occurs if the computer says 1 or 2 of the 3
> 
> names is in the guilty list.
> 
> 
> 
> With three names, and one candidate, the first two players are going on
> 
> sheer luck (if they guess wrong, the third player picks the third name
> 
> -- win). And with two candidates, you again have just three
> 
> possibilities: A & B, A & C, or B & C... So again the first two players
> 
> are just guessing, and if they don't guess right, the third player picks
> 
> the only remaining choice and wins.
> 
> 
> 
> 
> 
> 
> 
> -- 
> 
> 	Wulfraed                 Dennis Lee Bieber         AF6VN
> 
>         wlfraed@ix.netcom.com    HTTP://wlfraed.home.netcom.com/


 Thank You for the help. Now I am onto the coding part!!