Re: Common ancestor (visibility rules)

[Robert Dewar <robert_dewar@my-deja.com>]

In article <8bprin$a37$1@nnrp1.deja.com>,
  dmitry6243@my-deja.com wrote:
> Hello!
>
> Perhaps I've missed something

yup!

> but it seems that compilation units
> (except for library ones) do not have common ancestor.

of course they do, it is called standard, all library packages
are compiled within standard.


>    A.Foo; -- Error!

no exclamation mark needed, obviously A is not visible here!

> Now there is no way to use A.Foo in B.A, because B.A hides A.
The
> problem could be easily solved if all compilation unit had
have a common
> ancestor package, say "Root".

No need to invent a new name, it is called Standard


 Then package A could be specified as
> Root.A and A's Foo as Root.A.Foo.

Try Standard.A.Foo

> Interesting is that C++ has this
> feature.

Perhaps they copied it from Ada 95 :-)


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