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From: reinert <reinkor@gmail.com>
Subject: Re: ANN: Simple Components v
Date: Sun, 17 Jan 2021 08:20:29 -0800 (PST)	[thread overview]
Message-ID: <7d0f4046-76e7-47ae-ab56-751941fc1a5fn@googlegroups.com> (raw)
In-Reply-To: <ru0muk$1ar3$1@gioia.aioe.org>

I use it as part of a system processing scripts. The terms (a, b, c,..) and
operations (op1, op2,...) may represent functions to be defined.

reinert

søndag 17. januar 2021 kl. 07:54:16 UTC+1 skrev Dmitry A. Kazakov:
> On 2021-01-17 06:34, reinert wrote: 
> >>> Convert between prefix, infix, postfix notation? 
> >> Convert what? 
> >> -- 
> > 
> > Here is a reference to the topic: 
> > 
> > https://www.geeksforgeeks.org/convert-infix-prefix-notation: 
> > 
> > Simple example: 
> > 
> > a + b <-> +(a,b)
> And what is the problem? I mean this is trivial, or I do not understand 
> your question.
> > The expressions could be more complex: 
> > 
> > (a op1 b op2 (c + (d op3 e))) op4 ((f op5 g) op6) 
> > 
> > where op1, op2 etc are operators (functions). 
> > 
> > This may be standard for those making compilers. 
> > I use it to process sets (where operators are intersection, union etc) 
> > and a, b, c, ... above can be references to functions returning Ordered_Sets.
> I do not understand this either. Set-theoretic operations form a 
> lattice, no different from Ada's logical operations "and", "or", "not" 
> plus "in", "not in". Same rules. Are asking about syntax or types involved?
> -- 
> Regards, 
> Dmitry A. Kazakov 
> http://www.dmitry-kazakov.de

  reply	other threads:[~2021-01-17 16:20 UTC|newest]

Thread overview: 13+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2021-01-13 12:01 ANN: Simple Components v Dmitry A. Kazakov
2021-01-15 19:42 ` reinert
2021-01-15 20:05   ` Dmitry A. Kazakov
2021-01-17  5:34     ` reinert
2021-01-17  5:37       ` reinert
2021-01-17  6:54       ` Dmitry A. Kazakov
2021-01-17 16:20         ` reinert [this message]
2021-01-17 16:55           ` Shark8
2021-01-17 17:17             ` reinert
2021-01-17 17:38               ` Dmitry A. Kazakov
2021-01-18  6:50                 ` reinert
2021-01-17 17:27             ` Dmitry A. Kazakov
2021-01-17 17:26           ` Dmitry A. Kazakov
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