Re: Zeller's Algorithm

[Dan Nagle <dnagle@erols.com>]

Hello,

The Fortran 95 standard has two intrinsic functions,
mod() and modulo(), which have subtly different definitions.

I wonder which one the C++ committee thought they were modeling?

BTW, the Fortran 2000 standard doesn't change anything here,
so you can check this for free at http://www.j3-fortran.org
and clicking on Fortran 200x for a few megabytes of PDF
of the current draft standard.

-- 
Cheers!

Dan Nagle
Purple Sage Computing Solutions, Inc.

On Wed, 31 Jul 2002 16:01:27 -0400, Hyman Rosen <hyrosen@mail.com>
wrote:

>Darren New wrote:
>> Robert A Duff wrote:
>>>Doesn't this make the % operator totally useless for negative numbers?
>> Yes.
>
>No. It is required in C or C++ that for non-zero b,
>	a / b * b + a % b == a
>
>When division rounds towards zero, as is usually desired
>(the C++ standard claims that this is what the Fortran
>standard requires), this forces the remainder operation
>to return negative results. Eg., we want -3 / 2 == -1,
>so we must have -3 % 2 == -1 for the requirement to hold.