Re: understanding floating point types

[Ada novice <ycalleecharan@gmx.com>]

I have just read the following from an Ada book by Fintan Culwin:
----
type VeryAccurate is digits 16
type NotAccurate is digits 2

Values of the type VeryAccurate would have limited range with a high
degree of precision. Values of the type NotAccurate would have a much
greater range with only two digits of precision.
----

My understanding is that using "B = 3.32*D + 1", a type with digits 16
(D = 16) will have a higher B value and hence a higher exponent range
-4*B to 4*B than a type with digits 2. Will a higher exponent range
not give a higher range?

What am I understanding wrong here?

Thanks
YC