Re: How to do it in Ada ?

[Al Christians <alc@PublicPropertySoftware.com>]

with Ada.Text_IO;
with Ada.Command_Line;
procedure Initialize_Array is

   A:  Array(1..Integer'Value(Ada.Command_Line.Argument(1))) 
         of Integer := ( Others => 0 );
   begin
      -- The array is already initialized
      -- The following statements just show that it is
      Ada.Text_IO.Put( "First =" & Integer'Image(A'First));
      Ada.Text_IO.Put( "  First Value =" & Integer'Image(A(A'First)));
      Ada.Text_IO.Put( "  Last =" & Integer'Image(A'Last));
      Ada.Text_IO.Put( "  Last Vale=" & Integer'Image(A(A'Last)));
   end;      


Tomasz Wegrzanowski wrote:
> 
> int main(int argc, char **argv)
> {
>     int *x;
>     int n;
> 
>     n = (argc==1)?1:atoi(argv[1]);
>     x = malloc (n*sizeof(int));
>     for (x=0;x<n;x++)
>         x[i]=0;
> 
>     /* ... */
> }
> 
> Something like that ... how to do such dynamic array allocation in Ada ?