From: "DuckE" <nospam_steved@pacifier.com>
Subject: Re: Ada83 Exponentiation HELP !!!
Date: 1999/12/13
Date: 1999-12-13T00:00:00+00:00 [thread overview]
Message-ID: <3855ab32.0@news.pacifier.com> (raw)
In-Reply-To: 831tka$rue$1@tobruk.sydney.gecm.com
It's been years since I've dealt with evaluating things like this, but as I
recall 6^(1.3) is equivalent to:
Exp( 1.3 * Log( 6 ) )
Don't quote me on this, but it's somehting like that.
SteveD
jxredi <jxredi@gecms.com.au> wrote in message
news:831tka$rue$1@tobruk.sydney.gecm.com...
> Can anyone help me with the following :
>
> I understand that in Ada83, 6^3 is represented as 6**3, where 6 can
be
> int or real,
> and 3 can only be an INTEGER.
>
> So how do I represent in ada83 this ..... --> 6^(1.3) where 1.3 is
type
> REAL.
>
>
> Regards,
> Jxredi.
>
>
next prev parent reply other threads:[~1999-12-13 0:00 UTC|newest]
Thread overview: 8+ messages / expand[flat|nested] mbox.gz Atom feed top
1999-12-13 0:00 Ada83 Exponentiation HELP !!! jxredi
1999-12-13 0:00 ` DuckE [this message]
1999-12-14 0:00 ` Preben Randhol
1999-12-19 0:00 ` Robert Dewar
1999-12-19 0:00 ` Preben Randhol
1999-12-19 0:00 ` Robert Dewar
1999-12-13 0:00 ` David C. Hoos, Sr.
1999-12-13 0:00 ` Gautier
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