Re: Equality operator overloading in ADA 83

[clines@delete_this.airmail.net (Kevin Cline)]

"Manuel Wenger" <manuel@thunder.ch*> wrote:

>
>Hi,
>I've started doing some DecADA 83 programming at a technical engineering
>school ... and I've run into a problem that I was unable to solve (and my
>teacher didn't know any better either :-))
>
>I've tried to overload the "=" operator for fractions in a package. It
>obviously doesn't work if the type isn't defined as "limited private", and
>I don't want that. As an alternative, I found out that I might as well do a
>renaming declaration, just by defining the type as "private" - so I've
>tried doing that as well, and then using the following to rename the equal
>sign:
>
>In other words, how do I tell my "equal" function to be an equality
>operator, authorized to be renamed into "="? HELP! :)
>

You can't.  Period.  Why?  I don't know.  Drove me crazy once.
Maybe some Ada-83 committee member will volunteer why it was 
considered reasonable to redefine '<' and '>' but not '=' .