Re: Ada Smileys in C++ lib Conversion

[Maciej Sobczak <see.my.homepage@gmail.com>]

On 15 Sie, 03:16, Brian Drummond <brian_drumm...@btconnect.com> wrote:

> >Yes, this is a good practice. It is better to avoid using preprocessor
> >for anything other than so called include guards.
>
> Except when the result doesn't work!

If the result of *not* using preprocessor doesn't work, then with
preprocessor it would be even worse.

Can you give an example where using preprocessor works correctly,
whereas using typed constants does not?

> >Const means that the given name cannot be used to modify the referred
> >object and has nothing to do with the storage class (it might
> >influence the linkage, though).
>
> However, it does NOT mean the referred object cannot be modifed.

It cannot be modified via this name.

> Nor does it mean that you can use the object just anywhere you'd
> expect to use a constant.

Example, please. Example that shows that I cannot use const object
where constant is expected.

(Hint: there are some *very* obscure corner cases with templates, but
if you are there already, you are screwed anyway.)

> >> But it certainly puzzled me to be told that I couldn't use a "const" in a
> >> constant expression!
>
> >And what would that mean, anyway? How would you want to use it and
> >what would you like to achieve with it?
>
> In this instance I wanted to declare an array whose size was the constant
> expression in question.

const int size = 7;
int array[size];

Is this what you need? No problem with that.

--
Maciej Sobczak * http://www.inspirel.com

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