Re: Getting current date and time

[Maciej Sobczak <see.my.homepage@gmail.com>]

On 24 Lip, 17:24, Adam Beneschan <a...@irvine.com> wrote:

> > The problem is that I need just a number of seconds (this is for
> > interfacing with other software which uses that Unix-like time
> > descriptions), so I cannot use the value which is broken down into
> > several components.
>
> Why not?  Differences returns the result in "days" and "seconds", and
> you should be able to convert the "days" to seconds by multiplying it
> by a value that I just recently helped my 9-year-old figure out, and
> then adding the result to the second value, and then maybe adding the
> leap seconds (see below).

Right. I didn't notice that it's just two components, not more
(without years, months and days).

> We could
> conceivably propose a new addition to Ada.Calendar.Arithmetic:
>
> function
> Return_Current_Time_However_The_Other_Software_Maciej_Is_Using_Does_It;
>
> but I sort of doubt that a proposal like that would be accepted.

On my system Ada.Calendar.Time_Of and Ada.Calendar.Formatting.Time_Of
behave *differenty* with the same arguments, so with such a mess
already in the library no additional proposal could hurt...

Thank you for pointing me in the right direction, I was able now to
get the expected values by using Ada.Calendar.Formatting.Time_Of.

--
Maciej Sobczak
http://www.msobczak.com/