From: "Bob Fletcher" <fletcherr@logica.com>
Subject: Re: How to initiate part of a string?
Date: 1998/09/24
Date: 1998-09-24T00:00:00+00:00 [thread overview]
Message-ID: <01bde7ac$91707760$5330ea9e@UKP014459.logica.co.uk> (raw)
In-Reply-To: 35e45c89.12901035@SantaClara01.news.InterNex.Net
can't you do:
Txt: String(1..100) := (28..31=>"abcd", Others=>' ');
or am I missing the point;
Tom Moran <tmoran@bix.com> wrote in article
<35e45c89.12901035@SantaClara01.news.InterNex.Net>...
> > Txt : String(1 .. 100) := (1 .. 27=>' ') & "abcd" & (32 .. 100=>' ');
> vs
> > Txt : String(1 .. 100) := (1 .. 27=>' ') & "abcd" & (1 .. 69=>' ');
> The former has the advantage of less error-prone arithmetic required
> of the writer or readers of the code.
>
next prev parent reply other threads:[~1998-09-24 0:00 UTC|newest]
Thread overview: 16+ messages / expand[flat|nested] mbox.gz Atom feed top
1998-08-24 0:00 How to initiate part of a string? Hans Marqvardsen
1998-08-25 0:00 ` Tom Moran
1998-08-25 0:00 ` Samuel Tardieu
1998-08-26 0:00 ` Tom Moran
1998-08-26 0:00 ` Robert I. Eachus
1998-08-26 0:00 ` Tom Moran
1998-09-24 0:00 ` Bob Fletcher [this message]
1998-09-24 0:00 ` Tom Moran
1998-09-25 0:00 ` dewarr
1998-09-29 0:00 ` Aidan Skinner
1998-09-19 0:00 ` dewarr
1998-08-25 0:00 ` Mark A Biggar
1998-08-26 0:00 ` Frank Ecke
1998-08-26 0:00 ` Robert I. Eachus
1998-08-26 0:00 ` Mats Weber
1998-08-26 0:00 ` Frank Ecke
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