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From: Simon Wright <simon@pushface.org>
Newsgroups: comp.lang.ada
Subject: Re: whats semicolon?
Date: 23 Oct 2003 22:33:13 +0100
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"@{-_-}@" <nuhvok@terra.es> writes:

> Im triying to develop a code in ADA.  Im a newbie :).  This code must
> ouput a series number.
> 
> If I try a number N lagger than nought the program must ouput a
> progressive series number from 1 as far as N.
> 
> If I try a number N smaller than nought, the program must output a
> progressive series number from -1 as far as N.
> 
> If I try nouth the program must output "ZERO".
> 
> I tried the following intructions:
> 
> with Text_Io, Ada.Integer_Text_IO;
> use Text_Io, Ada.Integer_Text_IO;
> 
> procedure Practica1 is
> 
> n: integer;
> c: integer :=0;
> 
> begin
> 
> 	put ("Escribe un numero entero: ");
> 	get (n);
> 	if n = 0 then
> 
> 		put("cero")
> 
> 	else
> 	
> 		IF N > 0 then
> 			for c in 0..n loop
> 				put (c);
> 			end loop
> 		else
> 			for c in -1..n loop
> 				put (c);
> 			end loop
> 		end if
> 	
> 	end if
> 
> end Practica1;
> 
> When I try to compile it, the objectada show the following error:
> 
> practica1.adb: Error: line 20 col 2 Parse error: expected SEMICOLON,
> got ELSE, Inserting SEMICOLON
> 
> Whats SEMICOLON?

;

In Ada, the semicolon is a terminator not a separator.

   if n = 0 then
     put ("cero");
   else

(can you see that this fails to meet your requirements as stated in at
least two respects?)

Same semicolon problem later on at end loop;  end if; .

-- 
Simon Wright                               100% Ada, no bugs.