You are quite right.  I was thinking of the algorithm which always
rounds up if there is any remainder -- e.g., if you need to know how
many boxes are required to ship N items, if M items will fit in a box.

The algorithm you need (which will do the job without any comparisons
and conditional operations is

  (Dividend + Dividend + Divisor) / (Divisor + Divisor)

"Cephus�" <beau@hiwaay.net> wrote in message
news:vereehn58o9be1@corp.supernews.com...
>
>
> David C. Hoos wrote:
> > It's simpler to just add one less than the divisor to the dividend
> > before dividing.
>
>
> well look at if the total is 25. in your example, 25+3-1 = 27. That would
> give you 27/3 = 9
>
> but it is really 25/3 which equals 8 remainder 1 which is not enough to
> round up...
>
> Beau
>
>
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