From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: X-Spam-Status: No, score=-1.1 required=5.0 tests=BAYES_00, PP_MIME_FAKE_ASCII_TEXT autolearn=no autolearn_force=no version=3.4.4 X-Google-Language: ENGLISH,ASCII X-Google-Thread: 103376,efbbbab26bad9cb X-Google-Attributes: gid103376,public X-Google-ArrivalTime: 2003-06-16 05:21:26 PST Path: archiver1.google.com!news1.google.com!sn-xit-03!sn-xit-01!sn-post-01!supernews.com!corp.supernews.com!not-for-mail From: "Cephus�" Newsgroups: comp.lang.ada Subject: Re: how to round integers Date: Mon, 16 Jun 2003 07:12:08 -0500 Organization: Posted via Supernews, http://www.supernews.com Message-ID: References: X-Priority: 3 X-MSMail-Priority: Normal X-Newsreader: Microsoft Outlook Express 6.00.2800.1158 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1165 X-Complaints-To: abuse@supernews.com Xref: archiver1.google.com comp.lang.ada:39239 Date: 2003-06-16T07:12:08-05:00 List-Id: Charles LaCour wrote: > You would get 8 2/3 which becomes 8.66666.... This rounds up to nine > because .6 >= .5 > > I'm not an Ada programmer, but this question is not about Ada so I > thought it would be ok. > > "Cephus�" wrote in message > news:veqcdrsf7o7q57@corp.supernews.com... >> I am trying to remember the "golden rule" for integer division >> rounding. >> >> I am trying to average something (both integers) and I can't >> remember how to round without using floating point. >> >> Like say I am trying to divide 26/3 --- I would get 8 remainder 2 >> >> but that should round up to 9. How can I do this? I know it has >> something to do with the dividend....but I can't for the life of me >> remember. thanks! >> >> Beau no you can't do this because if you don't specifically type cast an integer into a float, you have no decimals. So if you say 26/3, you just get 8 in your variable...in other words it truncates the integer...