Charles LaCour wrote: > You would get 8 2/3 which becomes 8.66666.... This rounds up to nine > because .6 >= .5 > > I'm not an Ada programmer, but this question is not about Ada so I > thought it would be ok. > > "Cephus�" wrote in message > news:veqcdrsf7o7q57@corp.supernews.com... >> I am trying to remember the "golden rule" for integer division >> rounding. >> >> I am trying to average something (both integers) and I can't >> remember how to round without using floating point. >> >> Like say I am trying to divide 26/3 --- I would get 8 remainder 2 >> >> but that should round up to 9. How can I do this? I know it has >> something to do with the dividend....but I can't for the life of me >> remember. thanks! >> >> Beau no you can't do this because if you don't specifically type cast an integer into a float, you have no decimals. So if you say 26/3, you just get 8 in your variable...in other words it truncates the integer...