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From: Stephen Leake <stephen.a.leake.1@gsfc.nasa.gov>
Newsgroups: comp.lang.ada
Subject: Re: Dimensionality Checking (Ada 20XX)
Date: 13 Dec 2001 14:06:18 -0500
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daniele andreatta <andreatta@mail.chem.sc.edu> writes:

> Taylor series keeps the unit of the function. Basically the series is (as
> you recall)
> f(x) = f(x_0) + f'(x_0) (x-x_0) +f''(x_0) (x-x_0)**2 + ...
> and the unit of the derivatives are (indicating with [] the unit of the
> quantity)
> [f'(x)] = [f]/[x];    [f''] = [f]/[x]**2;    ....
> In the end
> [f(x)] = [Taylor expansion]

Ah. Yes. Of course. Silly of me. 

So in the expansion of Sin (x) = 1 - 1/6 x**3, the "1" and the "1/6"
have units, as does the "x".

Thanks!

> 
> 
> HTH, Daniel
> 
> 

-- 
-- Stephe