From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: X-Spam-Status: No, score=-1.9 required=5.0 tests=BAYES_00 autolearn=unavailable autolearn_force=no version=3.4.4 Path: eternal-september.org!reader01.eternal-september.org!reader02.eternal-september.org!feeder.eternal-september.org!goblin3!goblin2!goblin.stu.neva.ru!aioe.org!.POSTED!not-for-mail From: "Dmitry A. Kazakov" Newsgroups: comp.lang.ada Subject: Re: some trivial questions? Date: Fri, 10 Nov 2017 09:18:59 +0100 Organization: Aioe.org NNTP Server Message-ID: References: <6a5368c5-f015-4dcb-9291-e77b40fa1bf1@googlegroups.com> <39330489-ec8b-481f-bcff-a5b7d1a2d8e3@googlegroups.com> <7c68eace-8a03-4bfc-806d-aa78a453f97f@googlegroups.com> <651d0899-c38f-47f3-8f47-39fe726bc256@googlegroups.com> NNTP-Posting-Host: lKHBldubgAWx1EqbQpQ5LQ.user.gioia.aioe.org Mime-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed Content-Transfer-Encoding: 7bit X-Complaints-To: abuse@aioe.org User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:52.0) Gecko/20100101 Thunderbird/52.4.0 Content-Language: en-US X-Notice: Filtered by postfilter v. 0.8.2 Xref: feeder.eternal-september.org comp.lang.ada:48797 Date: 2017-11-10T09:18:59+01:00 List-Id: On 09/11/2017 23:52, AdaMagica wrote: > Am Donnerstag, 9. November 2017 22:38:31 UTC+1 schrieb Dmitry A. Kazakov: >> On 2017-11-09 22:11, AdaMagica wrote: >>> Am Donnerstag, 9. November 2017 21:05:21 UTC+1 schrieb Dmitry A. Kazakov: >>>> Also why should >>>> >>>> with A.B.C.D; >>>> >>>> imply >>>> >>>> with A, A.B, A.B.C; >>> >>> Do you think it shouldn't? >> >> No. Likewise >> >> use A.B.C; >> >> should imply >> >> with [,] [.]A, [.]A.B, [.]A.B.C; >> > I do not understand. You don't want "with A.B" to imply "with A", > but you want "use A.B" to imply "use A"? I want any obvious dependencies implied. >>> Children have direct visibility of their ancestors' visible part. >>> So why shouldn't "with A.B" imply "with A"? >> Playing devil's advocate, why visibility of A.B in C should imply that D >> depends on A.B when D has "with A.B.C;" > Then C depends on A.B, so if D depends on A.B.C, it also depends on A.B. Yes, and that dependency must be stated explicitly. No? -- Regards, Dmitry A. Kazakov http://www.dmitry-kazakov.de