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From: =?utf-8?Q?Yannick_Duch=C3=AAne_=28Hibou57?=
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Newsgroups: comp.lang.ada
Subject: Re: Specifying a target in a GPRBuild project file?
Date: Sat, 27 Apr 2013 10:37:37 +0200
Organization: Ada @ Home
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Date: 2013-04-27T10:37:37+02:00
List-Id: <comp.lang.ada>

Le Sat, 27 Apr 2013 08:05:35 +0200, Dmitry A. Kazakov  =

<mailbox@dmitry-kazakov.de> a =C3=A9crit:

>> which is somewhat equivalent to:
>>
>>    $ gprbuild --target=3Dx86-pc-vxworks foo.gpr
>
> Which wonders me how gprbuild might know the target. It should search =
for
> all installed cross compilers. Does it that? How? Which one gets  =

> selected?

It's all about GPRConfig, which is invoked behind the scene (precisely  =

something I personally prefer to be explicit, and that's why I'm in favo=
ur  =

of an explicit `--config` option=E2=80=A6 multiple opinions differs on t=
hat topic).

All the answers to your question are in section #2 of the GPRBuild User =
 =

Guide and in the GPRConfig database.

See: http://docs.adacore.com/gprbuild-docs/html/gprbuild_ug.html#Gprbuil=
d
This will tell you about how GPRBuild and GPRConfig works together.

See: `/usr/share/gprconfig/*.xml`
This will tell you how GPRConfig searchs for compilers and select the  =

appropriate one. This directory exists only if you have GPRBuild  =

installed. Note you may also give a `--db` option to GPRBuild, to extend=
  =

the database with you own database extension (that's what I do for my  =

compilers, as the default database only knows about GCC 4.6, while I'm  =

using GCC 4.8).

-- =

=E2=80=9CSyntactic sugar causes cancer of the semi-colons.=E2=80=9D [1]
=E2=80=9CStructured Programming supports the law of the excluded muddle.=
=E2=80=9D [1]
[1]: Epigrams on Programming =E2=80=94 Alan J. =E2=80=94 P. Yale Univers=
ity