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From: =?utf-8?Q?Yannick_Duch=C3=AAne_=28Hibou57?=
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 <yannick_duchene@yahoo.fr>
Newsgroups: comp.lang.ada
Subject: Re: Multiple dispatch
Date: Wed, 15 Jun 2011 13:19:22 +0200
Organization: Ada @ Home
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Date: 2011-06-15T13:19:22+02:00
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Le Wed, 15 Jun 2011 13:10:50 +0200, Yannick Duch=C3=AAne (Hibou57)  =

<yannick_duchene@yahoo.fr> a =C3=A9crit:
> A common and simple example, while not related to dispatching, is stre=
am  =

> operations : although its clear a input/ouput method must have two  =

> arguments, one for the stream and one for the data, how do you decide =
 =

> the operation belongs to the package defining the type or to the packa=
ge  =

> defining the stream.
I forget to say there is another alternative to that kind of ambiguity :=
  =

defining a third package. In that third package, both the stream type an=
d  =

the data type are treated equally, this is the package which represent t=
he  =

union or collaboration of both together, with no one of both looking lik=
e  =

dominated or controlled by the other (because there is no reason for the=
  =

design to act as if this was, as it is not). This obviously applies even=
  =

better when there are more than two types involved (but the question mos=
t  =

commonly raises when there are two types).


-- =

=E2=80=9CSyntactic sugar causes cancer of the semi-colons.=E2=80=9D  [Ep=
igrams on  =

Programming =E2=80=94 Alan J. =E2=80=94 P. Yale University]
=E2=80=9CStructured Programming supports the law of the excluded muddle.=
=E2=80=9D [Idem]
=E2=80=9Cc++; /* this makes c bigger but returns the old value */=E2=80=9D=
 [Anonymous]