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From: =?utf-8?Q?Yannick_Duch=C3=AAne_=28Hibou57?=
 =?utf-8?Q?=29?=
 <yannick_duchene@yahoo.fr>
Newsgroups: comp.lang.ada
Subject: Re: Fun: the Ada assignment operator is an alias of the equivalence
 operator
Date: Sat, 28 May 2011 11:19:09 +0200
Organization: Ada @ Home
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Date: 2011-05-28T11:19:09+02:00
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Le Sat, 28 May 2011 11:03:25 +0200, Dmitry A. Kazakov  =

<mailbox@dmitry-kazakov.de> a =C3=A9crit:
> I think it is a widely shared misconception that immutability has  =

> anything
> to do with that. [Functional is not an answer, whatever the question w=
as
> (:-))]
>
> No, even an initialized constant is not necessarily equivalent to its
> initializing expression. Obvious examples:
>
>    I : constant Integer :=3D Get (File);
>    X : constant Float :=3D Random (Dice);
>    T : constant Time :=3D Clock;

Right Er Professor, sure ":=3D" does not introduce a macro :p So, what a=
bout  =

=E2=80=9Cdefined-as the realization-of=E2=80=9D ?

> 2. Program equivalence. You can say that two programs are equivalent i=
n
> some [limited] sense, e.g. when the compiler optimizes the code, or wh=
en
> you modify the program.
Equivalent by realization (modulus some canonicalization of the output) =
?


-- =

=E2=80=9CSyntactic sugar causes cancer of the semi-colons.=E2=80=9D  [Ep=
igrams on  =

Programming =E2=80=94 Alan J. =E2=80=94 P. Yale University]
=E2=80=9CStructured Programming supports the law of the excluded muddle.=
=E2=80=9D [Idem]
=E2=80=9Cc++; /* this makes c bigger but returns the old value */=E2=80=9D=
 [Anonymous]