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From: =?utf-8?Q?Yannick_Duch=C3=AAne_=28Hibou57?=
 =?utf-8?Q?=29?=
 <yannick_duchene@yahoo.fr>
Newsgroups: comp.lang.ada
Subject: Re: Another question about fixed point types.
Date: Sun, 29 Aug 2010 08:32:46 +0200
Organization: Ada @ Home
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Date: 2010-08-29T08:32:46+02:00
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Le Sun, 29 Aug 2010 00:45:16 +0200, Peter C. Chapin <chapinp@acm.org> a =
 =

=C3=A9crit:
> That range does not include zero. However, the
> code above compiles and runs fine using GNAT GPL 2010.
I have never used fixed point type in Ada (nor floats by the way, but wi=
ll  =

do in the future for sound synthesis).
However, I had a look at the reference, and here is what it says which m=
ay  =

be relevant in your area:

ARM 2005 - 3.5.9 Fixed Point Types - says:

    12{base range (of a fixed point type) [partial]} The base range (see=
  =

3.5)
    of a fixed point type is symmetric around zero, except possibly for =
an  =

extra
    negative value in some implementations.

If it is symmetric around zero, that should explain your observations, a=
s  =

I would be very surprised if there would be provision for a hole  =

somewhere. If it is symmetric around zero, and there is no two disjoint =
 =

range, then this is include zero.

A tiny test program which would write first and last of the base type ma=
y  =

tell more.

Hint: note the =E2=80=9Cpossibly for an extra negative value in some  =

implementations=E2=80=9D, which may be important for you as you seems to=
 require  =

deep understanding of what's going on.

> P.S. The code above is a simplification of the real code, but I believ=
e
> it illustrates the question I have.
Yes, it seems it illustrates fine.

-- =

=E2=80=9CDual licensing is the Perl's way to disinfect the GNU General P=
ublic  =

Virus!=E2=80=9D (anonymous)