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From: mheaney@ni.net (Matthew Heaney)
Subject: Re: Ada function sqrt(x)
Date: 1996/09/22
Message-ID: <mheaney-ya023080002209961735440001@news.ni.net>#1/1
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references: <01bba50c$7c1a2760$dc014dc6@MountainNet> <51o7nh$5vl@cf01>
 <Dy0xBw.A1u@thomsoft.com>
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organization: Estormza Software
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newsgroups: comp.lang.ada
Date: 1996-09-22T00:00:00+00:00
List-Id: <comp.lang.ada>


> >I want to find the sqrt of a interger... how can I do this and what package
>> >do I need to declare
>[...]
>> If you are using Ada95 then the package is
>> 
>> Ada.Numerics.Generic_Elementary_Functions or
>> Ada.Numerics.Elementary_Functions (for a float instanciation).
>
>The original question was about finding the square root of an *integer*;
>Generic_Elementary_Functions and its instantiations work on floating-point
>types.

If you really want a function to do integer square roots, here it is (my
Ada 95 syntax may not be quite right):

   generic
      type T is range <>;
   function Generic_Square_Root (N : T) return T'Base;

   function Generic_Square_Root (N: T) return T'Base is
      The_Square_Root : T'Base := N/2;
   begin
      loop
         declare
            The_New_Value : constant T'Base := 
               (The_Square_Root + N / The_Square_Root) / 2;
         begin
            exit when The_New_Value = The_Square_Root;
         end;
      end loop;

      return The_Square_Root;
   end Generic_Square_Root; 

This will work in Ada 83, too, by removing the references to 'Base and
making sure type T has a large enough range to include the value of the
square root.

matt

--------------------------------------------------------------------
Matthew Heaney
Software Development Consultant
mheaney@ni.net
(818) 985-1271