From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: X-Spam-Status: No, score=-1.3 required=5.0 tests=BAYES_00,INVALID_MSGID autolearn=no autolearn_force=no version=3.4.4 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 103376,33411c81953c1a23 X-Google-Attributes: gid103376,public From: Preben Randhol Subject: Re: Ada83 Exponentiation HELP !!! Date: 1999/12/14 Message-ID: #1/1 X-Deja-AN: 560463076 References: <831tka$rue$1@tobruk.sydney.gecm.com> <3855ab32.0@news.pacifier.com> X-Complaints-To: usenet@itea.ntnu.no X-Trace: kopp.stud.ntnu.no 945164536 18438 129.241.83.82 (14 Dec 1999 09:42:16 GMT) Organization: ProgramVareVerkstedet NNTP-Posting-Date: 14 Dec 1999 09:42:16 GMT Newsgroups: comp.lang.ada Date: 1999-12-14T09:42:16+00:00 List-Id: "DuckE" writes: | It's been years since I've dealt with evaluating things like this, but as I | recall 6^(1.3) is equivalent to: | | Exp( 1.3 * Log( 6 ) ) ^^^ Just to make it clear, Log here must be the natural logarithm Ln Ln(a^b) = b*Ln(a) a^b = exp(b*Ln(a)) ; a > 0 Isn't this correct? -- Preben Randhol -- [randhol@pvv.org] -- [http://www.pvv.org/~randhol/] "Det eneste trygge stedet i verden er inne i en fortelling." -- Athol Fugard