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From: "Jeffrey R. Carter" <spam.jrcarter.not@nospam.acm.org>
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Subject: Re: Number of possible values in of enumerated type
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Date: 2009-06-08T21:45:53+00:00
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Gautier wrote:
>
> Did I overlook a specific attribute, or do I always need to write:
> 
>   Blah'Pos(Blah'Last)+1
> 
> for getting the number of possible values of an enumerated type ?

You didn't overlook anything. Note, however, that your solution fails for some 
constrained subtypes:

type E is (A, B, C);
subtype F is E range B .. C;

F'Pos (F'Last) = E'Pos (E'Last) = 2, so F'Pos (F'Last) + 1 gives 3, which is a 
problem if you want the number of values in subtype F (2). The general solution is

S'Pos (S'Last) - S'Pos (S'First) + 1

-- 
Jeff Carter
"Now look, Col. Batguano, if that really is your name."
Dr. Strangelove
31