Re: How to initialize a matrix of one column only?

["Nasser M. Abbasi" <nma@12000.org>]

On 7/7/2012 7:08 PM, Nasser M. Abbasi wrote:

> Here is the code, I write
>
> ----------------------
> with Interfaces.Fortran;
> use  Interfaces.Fortran;
> with lbase;
>     ....
>     N: Fortran_Integer := 3;
>     B: labase.Fortran_Real_Matrix ( 1..N, 1..1  );
> BEGIN
>     B := ((9.0) ,    -- here is the problem
>           (2.0) ,
>           (-2.0));
>     ....
> --------------------------------------------
....
>
> I tried B:=(1=>9.0,2=>2.03=>-2.0);
> and B := ((9.0 ,2.0 , 3));
> but non working.
>
> What is the correct syntax to use?
>

I found it !

But it makes no sense at al to me.  Here is the correct syntax

------------------
N:   Fortran_Integer := 3;	
B:   labase.Fortran_Real_Matrix ( 1..N, 1..1  );
BEGIN
B := ((9.0,  others=>0.0),
       (2.0,  others=>0.0),
       (-2.0, others=>0.0)
      );
----------------------

Why do I have to write others=>0.0 ? What others? there is
only 1 column? What Am I missing here?

--Nasser