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From: =?ISO-8859-1?Q?Hibou57_=28Yannick_Duch=EAne=29?=
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Subject: Re: How to convert a string containing two hex digits to a character?
Date: Wed, 6 Jan 2010 14:19:29 -0800 (PST)
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Date: 2010-01-06T14:19:29-08:00
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On 6 jan, 22:54, Maciej Sobczak <see.my.homep...@gmail.com> wrote:
>
> Sorry, but I find it to be overly paranoid.
> What has happened to the old good "Something + 1"?
No such thing as paranoia here, as any way, for numbers, X + 1 and
Number_Type'Succ (X) are strictly equivalent (thus, the Succ function
attribute is not more paranoid than the =93 + =94 operator).

As the question was from a student, I was just trying to give him/her
some food for dinner. It's always good to know about Succ : it is
required with enumerated types, and it is the only way to do something
like =93 + 1 =94 when a numeric type is passed as a formal discrete type
parameter of a generic.