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From: "Bob Spooner" <rls19@psu.edu>
Newsgroups: comp.lang.ada
Subject: Re: Using GNAT.Sockets
Date: Fri, 15 Apr 2005 10:07:17 -0400
Organization: Penn State University, Center for Academic Computing
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Date: 2005-04-15T10:07:17-04:00
List-Id: <comp.lang.ada>

Well, it's not _quite_ that simple...
"Michael Paus" <pausnospam@nospamib-paus.com> wrote in message
news:d3o9le$cgm$1@online.de...
> markp wrote:
>
> > Bob,
> >
> > Thanks for your reply. My basic quesion is I realize that a socket read
> > will not necessarily return all the data requested. The Receive_Socket
> > item input parameter takes and array. Will a subsequent read place data
> > at the beginning of the array, meaning I have to copy data out before I
> > read again?
>
> Yes it does but you do not have to copy your data. Just have a look at
> Duncans example. He told you already how to do it. You just have to call
> this in a loop until Last = My_Buffer'Last.
>
>    procedure Receive_Socket
>      (Socket => My_Socket,
>       Item   => My_Buffer (Last + 1 .. My_Buffer'Last),
>       Last   => Last);
>
> The first byte will be stored at the first position of the buffer array
> you provide, but in the above example we specify a sub-range of the
> whole buffer and so the first element of this is at the index Last + 1
> of the whole buffer and this is exactly what you need.
>
> Michael

Your buffer needs to be big enough to read the largest message you expect,
and for the shorter messages, you need to use a slice of the buffer equal to
the size of the message being read so that you don't read in some of the
following message along with the current message.

Bob