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From: Henrique <henriquemagalhaes@gmail.com>
Newsgroups: comp.lang.ada
Subject: Re: Float conversion
Date: Thu, 29 Jul 2010 11:21:52 -0700 (PDT)
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Date: 2010-07-29T11:21:52-07:00
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On Jul 29, 12:35=A0pm, "Dmitry A. Kazakov" <mail...@dmitry-kazakov.de>
wrote:
> ------------------------
> var1 9.99900024414063E+02
> var4 9.99900085449219E+02
>
> When rounded to 6 decimal digits both are same. But the underlying base
> binary type is longer than 6 digits.
>
> P.S. It is always useful to think of floating point numbers as intervals
> (which they are) rather than numbers.
>
> --
> Regards,
> Dmitry A. Kazakovhttp://www.dmitry-kazakov.de

As I declared the type with 6 digits, I expected that it would make
the comparison only for these digits (this would gave var4 =3D var1).

Do I always need to manually truncate the float number to the number
of desired digits before making a comparison of them?? So what is the
advantage of declaring it as "digits 6"?

Thanks