You would get 8 2/3 which becomes 8.66666....  This rounds up to nine
because .6 >= .5

I'm not an Ada programmer, but this question is not about Ada so I thought
it would be ok.

"Cephus�" <beau@hiwaay.net> wrote in message
news:veqcdrsf7o7q57@corp.supernews.com...
> I am trying to remember the "golden rule" for integer division rounding.
>
> I am trying to average something (both integers) and I can't remember how
to
> round without using floating point.
>
> Like say I am trying to divide 26/3  --- I would get 8 remainder 2
>
> but that should round up to 9. How can I do this? I know it has something
to
> do with the dividend....but I can't for the life of me remember. thanks!
>
> Beau
>
>