Re: implementation approach

["SteveD" <nospam_steved94@attbi.com>]

"Mark" <ma740988@pegasus.cc.ucf.edu> wrote in message
news:a5ae824.0207301854.3295f3a2@posting.google.com...
[snip]
>
> I suspect I'll need two semaphores on both processors.  Once the flag
> gets passed from processor B to processor A, the routine in A will
> enter the semaphore command the device, release the flag, etc.
>
> Thanks in advance

In Ada an interrupt is associated with a protected procedure in a protected
type.  An example of how to set this up is in the LRM C.3.2(28).

I haven't done any Ada Interrupt handling myself, but I believe this is the
way it's done.

With Ada.Interrupts;

Package Body Interrupt_Test Is

  Protected Type Device_Interface(Int_Id : Ada.Interrupts.Interrupt_ID) Is
    Procedure Handler;
    Pragma Attach_Handler( Handler, Int_Id );
    Entry Wait_Interrupt;
  Private
    Occurred : Boolean := False;
  End Device_Interface;

  Protected Body Device_Interface Is
    Procedure Handler Is
    Begin
      Occurred := TRUE;
    End Handler;
    Entry Wait_Interrupt When Occurred Is
    Begin
      Occurred := False;
    End Wait_Interrupt;
  End Device_Interface;

  Device_1_Driver : Device_Interface( 1 );

  Task Relay Is
  End Relay;

  Task Body Relay Is
  Begin
    Loop
      Device_1_Driver.Wait_Interrupt;
      -- Do something when the interrupt occurs
    End Loop;
  End Relay;

End Interrupt_Test;


I hope this helps,
SteveD