From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: ** X-Spam-Status: No, score=2.2 required=5.0 tests=BAYES_00,INVALID_MSGID, PDS_OTHER_BAD_TLD,REPLYTO_WITHOUT_TO_CC autolearn=no autolearn_force=no version=3.4.4 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: fac41,9a0ff0bffdf63657 X-Google-Attributes: gidfac41,public X-Google-Thread: 1108a1,9a0ff0bffdf63657 X-Google-Attributes: gid1108a1,public X-Google-Thread: f43e6,9a0ff0bffdf63657 X-Google-Attributes: gidf43e6,public X-Google-Thread: 103376,4b06f8f15f01a568 X-Google-Attributes: gid103376,public From: nospam@thanks.com.au (Don Harrison) Subject: Re: Software landmines (loops) Date: 1998/09/01 Message-ID: #1/1 X-Deja-AN: 386669622 Sender: news@syd.csa.com.au X-Nntp-Posting-Host: dev7 References: Organization: CSC Australia, Sydney Reply-To: nospam@thanks.com.au Newsgroups: comp.lang.eiffel,comp.object,comp.software-eng,comp.lang.ada Date: 1998-09-01T00:00:00+00:00 List-Id: Matthew Heaney wrote (to support the notion of multiple returns): :Here's is something I whipped up for another post recently. It's an :equality operator for a bounded stack. : :The implementation of the function has multiple returns. : :Does this implementation fit your definition of spaghetti code? : :Would the implementation be better by not using multiple returns? : : :function "=" (L, R : Stack_Type) return Boolean is :begin : : if L.Top /= R.Top then : return False; : end if; : : for Index in Positive range 1 .. L.Top loop : if L.Items (Index) /= R.Items (Index) then : return False; : end if; : end loop; : : return True; : :end "="; : : :My feeling is that trying to implement this operation using only a :single return would just make it more complicated. Not really. It's about the same (and the flow of control is clearer IMHO): function "=" (L, R : Stack_Type) return Boolean is Result : Boolean; begin Result := True; if L.Top /= R.Top then Result := False; else for Index in Positive range 1 .. L.Top loop if L.Items (Index) /= R.Items (Index) then Result := False; exit; end if; end loop; end if; return Result; end "="; Don (Harrison). donh at syd.csa.com.au Eiffel - Software engineering with class