From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: X-Spam-Status: No, score=-1.3 required=5.0 tests=BAYES_00,INVALID_MSGID autolearn=no autolearn_force=no version=3.4.4 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: fac41,2c6139ce13be9980 X-Google-Attributes: gidfac41,public X-Google-Thread: 103376,3d3f20d31be1c33a X-Google-Attributes: gid103376,public From: bobduff@world.std.com (Robert A Duff) Subject: Re: Precondition Checking For Ada 0X (Was: Separation of IF and Imp: process issue?) Date: 1997/09/16 Message-ID: #1/1 X-Deja-AN: 273076919 References: <341eac5e.0@news.uni-ulm.de> <184347314wnr@eiffel.demon.co.uk> Organization: The World Public Access UNIX, Brookline, MA Newsgroups: comp.lang.ada,comp.lang.eiffel Date: 1997-09-16T00:00:00+00:00 List-Id: In article <184347314wnr@eiffel.demon.co.uk>, Roger Browne wrote: >The client doesn't need to examine the invariant directly, because the >invariant must be satisfied any time the object is accessible to the client. My understanding is that the compiler generates run-time checks for invariants at both entry to and exit from each feature. Is that correct? If so, why? How can the check-upon-entry ever fail, since the invariant must be true initially, and must be true after every exit? - Bob