> Right, but "delay 0.0;" will cause the task to go to the end of its
> ready queue, so if there's any other task of the same priority waiting
> to run, it will run.  So "delay 0.0;" does what some systems call
> "yield".  (Assuming Annex D.)
>


To quote the LRM:
The execution time of a delay_statement that does not cause the task to be
blocked (e.g. �delay 0.0;� ) is of interest in situations where delays are
used to achieve voluntary round-robin task dispatching among equal-priority
tasks. (D.9 (14))

Ehud Lamm